A New Approach To Sovereign Debt Restructuring
By A. Krueger. 2002
317 citations recorded by the source corpus.
Subfields: Finance
View Paper: https://www.semanticscholar.org/paper/a6d34452118392a1cfe9c35815112fdad2076732
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Citations in the corpus
- Debt Maturity and the International Financial Architecture (2004, unknown): “A prominent example of the statutory approach was the sovereign debt restructuring mechanism (SDRM) proposed by the IMF s Anne Krueger (Krueger, 2002).”
- The case for GDP‐indexed bonds (2004, unknown): “or contractual mechanisms to manage debt restructuring in cases when default occurs (Krueger, 2002; Rogoff and Zettelmeyer, 2002), the drafting of ‘codes of conduct’ for investors and sovereigns, and the potential for IMF loans to generate moral hazard ( Jeanne and Zettelmeyer, 2001).”
- Toward a Statutory Approach to Sovereign Debt Restructuring: Lessons from Corporate Bankruptcy Practice around the World (2003, unknown): “References ................................................................................................................................ 32 - 3 - I. INTRODUCTIO:-; The IMF's (200 I, 2002) recent proposals for the introduction of a sovereign debt restructuring forum to facilitate the resolution of”
- A European mechanism for sovereign debt crisis resolution: a proposal. Bruegel Blueprint Series, 9 November 2010 (2010, background): “8,9 Earlier in this decade, the IMF presented a proposal for a Sovereign Debt Restructuring Mechanism (Krueger, 2002; Rogoff and Zettelmeyer, 2002a, b) to deal with defaults of developing and emerging market countries, which is discussed in detail in the next section.”
- Sovereign Debt without Default Penalties (2009, unknown): “Applying the implicit function theorem to (25) yields, after some calculations, dR/dB > 0.”
- Holdouts in Sovereign Debt Restructuring: A Theory of Negotiation in a Weak Contractual Environment (2012, unknown): “In (36) we have v0 N+1 = vN ; v 0 N = vN 1; ; v0 i+1 = vi; ; v0 2 = v: Therefore i+1 i = v0 i+1= 0 i+1 vi= i = i i+1 = 1 i (v1 + + vi) 1 i+1 (v0 1 + v1 + + vi) < 1”