A refinement of a congruence result by van Hamme and Mortenson

By Zhi-Wei Sun. 2010

47 citations recorded by the source corpus.

Let $p$ be an odd prime. In 2008 E. Mortenson proved van Hamme's following conjecture: $$\sum_{k=0}^{(p-1)/2}(4k+1)\binom{-1/2}k^3\equiv (-1)^{(p-1)/2}p\pmod{p^3}.$$ In this paper we show further that \begin{align*}\sum_{k=0}^{p-1}(4k+1)\binom{-1/2}k^3\equiv &\sum_{k=0}^{(p-1)/2}(4k+1)\binom{-1/2}k^3 \\\equiv & (-1)^{(p-1)/2}p+p^3E_{p-3} \pmod{p^4},\end{align*}where $E_0,E_1,E_2,\ldots$ are Euler numbers. We also prove that if $p>3$ then $$\sum_{k=0}^{(p-1)/2}\frac{20k+3}{(-2^{10})^k}\binom{4k}{k,k,k,k}\equiv(-1)^{(p-1)/2}p(2^{p-1}+2-(2^{p-1}-1)^2)\pmod{p^4}.$$

Subfields: Algebra and Number Theory, Discrete Mathematics and Combinatorics

View Paper: https://www.semanticscholar.org/paper/745043c00bcee9aa820eb46a97320b0be0d833c8

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In Algebra and Number Theory

  1. Ji-Cai Liu
  2. Victor J. W. Guo
  3. Wadim Zudilin
  4. Michael J. Schlosser
  5. Su-Dan Wang
  6. Armin Straub

In Discrete Mathematics and Combinatorics

  1. Ji-Cai Liu
  2. Victor J. W. Guo
  3. Michael J. Schlosser
  4. Su-Dan Wang

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