A class of solutions to stationary Stokes and Navier-Stokes equations with boundary data in W−1/q,q
By Giovanni P. Galdi, Christian Simader, H. Sohr. 2005
103 citations recorded by the source corpus.
Subfields: Applied Mathematics, Computational Theory and Mathematics, Mathematical Physics
View Paper: https://www.semanticscholar.org/paper/433f72b645095eb5adf76af76f02b6b659e48b2e
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In Applied Mathematics
- Hyunseok Kim
- María Ángeles Rodríguez-Bellido
- Chérif Amrouche
- H. Sohr
- Reinhard Farwig
- Giovanni P. Galdi
- Jean-Pierre Raymond
- Yonggeun Cho
In Computational Theory and Mathematics
In Mathematical Physics
- Hyunseok Kim
- Chérif Amrouche
- María Ángeles Rodríguez-Bellido
- H. Sohr
- Reinhard Farwig
- Giovanni P. Galdi
- Jean-Pierre Raymond
- Yonggeun Cho
Citations in the corpus
- Existence and Regularity of Very Weak Solutions of the Stationary Navier–Stokes Equations (2009, methodology): “On the other hand, the notion of very weak solutions has been introduced by Giga [12], Conca [3], Galdi et al. [ 9 ] and Farwig et al. [4,5] to prove unique solvability of the Stokes equations with very irregular boundary data, that is, boundary data in L q (∂Ω) or more generally in W −1/q,q (∂Ω).”
- State-constrained optimal control of the three-dimensional stationary Navier–Stokes equations☆ (2008, unknown): “In the fluid mechanics context, this type of solutions have been considered in [16] for problems with boundary data in spaces of low regularity.”
- Stationary Stokes, Oseen and Navier–Stokes Equations with Singular Data (2011, background): “Observe that in [21] Theorem 3, the domain considered is of class C2,1 instead of class C1,1, and the divergence term h ∈ L p( ) instead of h ∈ Lr ( ).”
- A New Class of Weak Solutions of the Navier–Stokes Equations with Nonhomogeneous Data (2006, background): “To prove uniqueness we follow [ 15 ] and assume that there exists another very weak solution v ∈ L q () of the system (1.8) with the same data F, k, g as for u. Setting U = u − v we can show that the equation h U, ¢w + v ¢ ∇ w + u ¢ (∇w) T + kwi = 0 (3.24)”